How much heat must be removed to cool 1000 lbs of water from 72 degrees F to -18 degrees F?

Study for the Mohawk Basic AC and Refrigeration Exam. Utilize flashcards and multiple-choice questions, with hints and explanations for each item. Get exam-ready today!

Multiple Choice

How much heat must be removed to cool 1000 lbs of water from 72 degrees F to -18 degrees F?

Explanation:
To determine how much heat must be removed to cool 1000 lbs of water from 72 degrees F to -18 degrees F, we need to account for both the cooling of the water from 72 degrees F to 32 degrees F (the freezing point) and then the additional heat removal needed to freeze the water and cool it down to -18 degrees F. First, calculate the heat removed to cool the water from 72 degrees F to 32 degrees F using the specific heat of water, which is approximately 1 BTU/lb°F: 1. **Cooling from 72°F to 32°F:** Temperature change = 72 - 32 = 40°F Heat removed for cooling = mass × specific heat × temperature change = 1000 lbs × 1 BTU/lb°F × 40°F = 40,000 BTU Next, we need to calculate the heat removed to freeze the water at 32 degrees F. The latent heat of fusion for water is about 144 BTU/lb: 2. **Freezing the water:** Heat removed to freeze 1000 lbs of water = mass × latent heat of fusion = 1000

To determine how much heat must be removed to cool 1000 lbs of water from 72 degrees F to -18 degrees F, we need to account for both the cooling of the water from 72 degrees F to 32 degrees F (the freezing point) and then the additional heat removal needed to freeze the water and cool it down to -18 degrees F.

First, calculate the heat removed to cool the water from 72 degrees F to 32 degrees F using the specific heat of water, which is approximately 1 BTU/lb°F:

  1. Cooling from 72°F to 32°F:

Temperature change = 72 - 32 = 40°F

Heat removed for cooling = mass × specific heat × temperature change

= 1000 lbs × 1 BTU/lb°F × 40°F

= 40,000 BTU

Next, we need to calculate the heat removed to freeze the water at 32 degrees F. The latent heat of fusion for water is about 144 BTU/lb:

  1. Freezing the water:

Heat removed to freeze 1000 lbs of water = mass × latent heat of fusion

= 1000

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